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Voltage drop calculator

Estimate voltage drop from the conductor resistance you enter—using an explicit outgoing-and-return path, without selecting a cable or making a code-compliance judgment.

Explicit two-conductor resistance path

Enter source-to-load length once. The calculation doubles it for the outgoing and return conductors.

Estimated voltage drop
200 mV
0.8333% · of source voltage
Estimated load voltage
23.8 V
Total loop resistance
40 mΩ
Total loop length
20 m
Conductor loss at entered current
1 W
Formula and substitution
Rloop = 2 × L × r; ΔV = I × Rloop
2 × 10 m × 0.002 Ω/m; then 5 A × 0.04 Ω

Manual-resistance estimate only. No conductor sizing, ampacity, temperature correction, reactance, installation method, protection or compliance verdict.

Included

  • Two-conductor DC and resistive single-phase paths
  • Manual resistance per length in metric or foot-based units
  • Voltage drop, percentage, load voltage, loop resistance and I²R loss

Not included

  • Conductor-size recommendations or material presets
  • Ampacity, temperature, reactance, installation method and protection
  • Local voltage-drop limits or compliance verdicts

What this means

The entered length is one way. Current travels to the load and back, so this narrow two-conductor model uses a loop length of 2 × L. Total loop resistance is that loop length multiplied by the entered resistance per length.

Ohm's law then gives ΔV = I × R<sub>loop</sub>. The percentage is the drop divided by source voltage, and estimated load voltage is source voltage minus the drop.

The calculator never chooses a conductor. Use a resistance value that already reflects the conductor and temperature basis you intend to examine, then take real installation decisions to qualified local guidance.

Formula & worked example

Rloop = 2 × L × r
ΔV = I × Rloop
Drop % = ΔV ÷ Vsource × 100
Vload = Vsource − ΔV

24 V DC, 5 A, 10 m one-way length and 2 Ω/km conductor resistance

Loop resistance
2 × 10 m × 0.002 Ω/m = 0.04 Ω
Voltage drop
5 A × 0.04 Ω = 0.20 V
Estimated load voltage
24.00 − 0.20 = 23.80 V

The entered resistance implies a 0.833% drop and 1 W of conductor loss at the stated current.

How this calculation works

The calculation follows the formulas, definitions and assumptions explained on this page. The references below support the method and any stated boundaries.

Official sources

Common questions

Why does the calculator double the entered length?
The length field is one way from source to load. This two-conductor model includes both the outgoing and return conductors, so the electrical path is twice that length.
Why are there no cable-size presets?
Resistance changes with material, cross-section, construction and temperature. Requiring an explicit resistance per length keeps the calculation inspectable and avoids presenting a generic preset as a design recommendation.
Does a low percentage mean the installation is compliant?
No. The result is only an estimate from entered resistance. It does not check ampacity, protection, temperature, reactance, installation method or local rules.

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