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Three-phase power calculator

Solve a balanced three-phase system from line-to-line voltage, line current and power factor—with electrical input power and useful output kept separate.

Balanced line-value calculation

Power factor acts between apparent and real electrical input power. Efficiency acts after that, between electrical input and useful output.

Electrical input real power
5.543 kW
Line-to-line voltage
400 V
Line current
10 A
Electrical input real power
5.543 kW
Useful output power
4.988 kW
Apparent power
6.928 kVA
Reactive power magnitude
4.157 kvar
Input-to-output loss
0.554 kW
Formula and substitution
P₁ = √3 × VLL × IL × PF; P₂ = P₁ × η
√3 × 400 V × 10 A × 0.8; then × 0.9

Balanced sinusoidal three-phase line values only. No unbalance, harmonics, conductor or protection sizing, installation advice or compliance verdict.

Included

  • Balanced sinusoidal three-phase systems
  • Line-to-line voltage and line current only
  • Real, apparent and reactive power with separate output efficiency

Not included

  • Phase-to-neutral inputs, unbalanced loads and harmonics
  • Cable, breaker, transformer or protection sizing
  • Installation, code-compliance or safety approval

What this means

For a balanced three-phase system, apparent power is S = √3 × V<sub>LL</sub> × I<sub>L</sub>. Real electrical input power is P₁ = S × PF. Reactive power follows the power triangle: Q = √(S² − P₁²).

Efficiency is deliberately separate from power factor. Power factor describes the relationship between real and apparent electrical power; efficiency compares useful output power with real electrical input power.

Every voltage and current field is a line value. The calculator does not accept or infer phase-to-neutral voltage, so the √3 factor is never mixed with an ambiguous phase convention.

Formula & worked example

S = √3 × VLL × IL
P₁ = S × PF
Q = √(S² − P₁²)
P₂ = P₁ × η

400 V line-to-line, 10 A line current, 0.80 power factor and 90% efficiency

Apparent power
√3 × 400 × 10 = 6.928 kVA
Electrical input real power
6.928 × 0.80 = 5.543 kW
Useful output power
5.543 × 0.90 = 4.988 kW

Power factor reduces real power relative to apparent power; efficiency then reduces useful output relative to real electrical input.

How this calculation works

The calculation follows the formulas, definitions and assumptions explained on this page. The references below support the method and any stated boundaries.

Official sources

Common questions

Should I enter line-to-line or phase voltage?
Enter line-to-line RMS voltage only. This calculator does not accept phase-to-neutral voltage and does not infer a star or delta connection.
What is the difference between power factor and efficiency?
Power factor is real electrical input power divided by apparent power. Efficiency is useful output power divided by real electrical input power. They describe different losses or effects and are applied separately.
Can I use this to size a cable, breaker or transformer?
No. It solves a narrow balanced-system power relationship. Equipment and conductor selection needs ratings, duty, installation conditions, protection rules and local requirements that are not included here.

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